1/2(10x-7)=5x+8

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Solution for 1/2(10x-7)=5x+8 equation: 



1/2(10x-7)=5x+8

We move all terms to the left:

1/2(10x-7)-(5x+8)=0



Domain of the equation: 2(10x-7)!=0

x∈R



We get rid of parentheses

1/2(10x-7)-5x-8=0

We multiply all the terms by the denominator


-5x*2(10x-7)-8*2(10x-7)+1=0

Wy multiply elements

-10x^2(1-16x(1+1=0

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