1/2(10y+2)+3=14

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Solution for 1/2(10y+2)+3=14 equation: 



1/2(10y+2)+3=14

We move all terms to the left:

1/2(10y+2)+3-(14)=0



Domain of the equation: 2(10y+2)!=0

y∈R



We add all the numbers together, and all the variables

1/2(10y+2)-11=0

We multiply all the terms by the denominator


-11*2(10y+2)+1=0

Wy multiply elements

-22y(1+1=0

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