1/2(10y+4)=4y+3+y

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Solution for 1/2(10y+4)=4y+3+y equation:



1/2(10y+4)=4y+3+y
We move all terms to the left:
1/2(10y+4)-(4y+3+y)=0
Domain of the equation: 2(10y+4)!=0
y∈R
We add all the numbers together, and all the variables
1/2(10y+4)-(5y+3)=0
We get rid of parentheses
1/2(10y+4)-5y-3=0
We multiply all the terms by the denominator
-5y*2(10y+4)-3*2(10y+4)+1=0
Wy multiply elements
-10y^2(1-6y(1+1=0

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