1/2(10y+4)=4y+3+y

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Solution for 1/2(10y+4)=4y+3+y equation: 



1/2(10y+4)=4y+3+y

We move all terms to the left:

1/2(10y+4)-(4y+3+y)=0



Domain of the equation: 2(10y+4)!=0

y∈R



We add all the numbers together, and all the variables

1/2(10y+4)-(5y+3)=0

We get rid of parentheses

1/2(10y+4)-5y-3=0

We multiply all the terms by the denominator


-5y*2(10y+4)-3*2(10y+4)+1=0

Wy multiply elements

-10y^2(1-6y(1+1=0

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