1/2(10y-2)+4y=-25

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Solution for 1/2(10y-2)+4y=-25 equation: 



1/2(10y-2)+4y=-25

We move all terms to the left:

1/2(10y-2)+4y-(-25)=0



Domain of the equation: 2(10y-2)!=0

y∈R



We add all the numbers together, and all the variables

4y+1/2(10y-2)+25=0

We multiply all the terms by the denominator


4y*2(10y-2)+25*2(10y-2)+1=0

Wy multiply elements

8y^2(1+50y(1+1=0

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