1/2(12-j)=6

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Solution for 1/2(12-j)=6 equation: 



1/2(12-j)=6

We move all terms to the left:

1/2(12-j)-(6)=0



Domain of the equation: 2(12-j)!=0

j∈R



We add all the numbers together, and all the variables

1/2(-1j+12)-6=0

We multiply all the terms by the denominator


-6*2(-1j+12)+1=0

Wy multiply elements

-12j(-+1=0

We use the square of the difference formula

-12j(-1=0

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