1/2(12a-4)-10a=-26

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Solution for 1/2(12a-4)-10a=-26 equation: 



1/2(12a-4)-10a=-26

We move all terms to the left:

1/2(12a-4)-10a-(-26)=0



Domain of the equation: 2(12a-4)!=0

a∈R



We add all the numbers together, and all the variables

-10a+1/2(12a-4)+26=0

We multiply all the terms by the denominator


-10a*2(12a-4)+26*2(12a-4)+1=0

Wy multiply elements

-20a^2(1+52a(1+1=0

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