1/2(12x+10)=1/3(6x+12)

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Solution for 1/2(12x+10)=1/3(6x+12) equation: 



1/2(12x+10)=1/3(6x+12)

We move all terms to the left:

1/2(12x+10)-(1/3(6x+12))=0



Domain of the equation: 2(12x+10)!=0

x∈R





Domain of the equation: 3(6x+12))!=0

x∈R



We calculate fractions


(3x6/(2(12x+10)*3(6x+12)))+(-2x1/(2(12x+10)*3(6x+12)))=0



We calculate terms in parentheses: +(3x6/(2(12x+10)*3(6x+12))), so:

3x6/(2(12x+10)*3(6x+12))

We multiply all the terms by the denominator


3x6

We add all the numbers together, and all the variables

3x^6

We do not support expression: x^6

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