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1/2(12x+3)-3=3(7-3x)
We move all terms to the left:
1/2(12x+3)-3-(3(7-3x))=0
Domain of the equation: 2(12x+3)!=0We add all the numbers together, and all the variables
x∈R
1/2(12x+3)-(3(-3x+7))-3=0
We multiply all the terms by the denominator
-((3(-3x+7)))*2(12x+3)-3*2(12x+3)+1=0
We calculate terms in parentheses: -((3(-3x+7)))*2(12x+3), so:Wy multiply elements
(3(-3x+7)))*2(12x+3
-((3(-3x+7)))*2(12x+3)-6x(1+1=0
We calculate terms in parentheses: -((3(-3x+7)))*2(12x+3), so:
(3(-3x+7)))*2(12x+3
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(3(-3x+7)))*2(12x+3
We calculate terms in parentheses: -((3(-3x+7)))*2(12x+3), so:
(3(-3x+7)))*2(12x+3
We calculate terms in parentheses: -((3(-3x+7)))*2(12x+3), so:
(3(-3x+7)))*2(12x+3
We calculate terms in parentheses: -((3(-3x+7)))*2(12x+3), so:
(3(-3x+7)))*2(12x+3
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(3(-3x+7)))*2(12x+3
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(3(-3x+7)))*2(12x+3
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(3(-3x+7)))*2(12x+3
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(3(-3x+7)))*2(12x+3
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(3(-3x+7)))*2(12x+3
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(3(-3x+7)))*2(12x+3
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(3(-3x+7)))*2(12x+3
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(3(-3x+7)))*2(12x+3
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(3(-3x+7)))*2(12x+3
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(3(-3x+7)))*2(12x+3
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(3(-3x+7)))*2(12x+3
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(3(-3x+7)))*2(12x+3
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