1/2(13x+5x-6-8x+14)=1/2(10x+8)

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Solution for 1/2(13x+5x-6-8x+14)=1/2(10x+8) equation: 



1/2(13x+5x-6-8x+14)=1/2(10x+8)

We move all terms to the left:

1/2(13x+5x-6-8x+14)-(1/2(10x+8))=0



Domain of the equation: 2(13x+5x-6-8x+14)!=0

x∈R





Domain of the equation: 2(10x+8))!=0

x∈R



We add all the numbers together, and all the variables

1/2(10x+8)-(1/2(10x+8))=0

We calculate fractions


(2x1/(2(10x+8)*2(10x+8)))+(-2x1/(2(10x+8)*2(10x+8)))=0



We calculate terms in parentheses: +(2x1/(2(10x+8)*2(10x+8))), so:

2x1/(2(10x+8)*2(10x+8))

We multiply all the terms by the denominator


2x1

We add all the numbers together, and all the variables

2x

Back to the equation:

+(2x)





We calculate terms in parentheses: +(-2x1/(2(10x+8)*2(10x+8))), so:

-2x1/(2(10x+8)*2(10x+8))

We multiply all the terms by the denominator


-2x1

We add all the numbers together, and all the variables

-2x

Back to the equation:

+(-2x)



We get rid of parentheses

2x-2x=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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