1/2(14m+4)=1/3(9m+12)

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Solution for 1/2(14m+4)=1/3(9m+12) equation: 



1/2(14m+4)=1/3(9m+12)

We move all terms to the left:

1/2(14m+4)-(1/3(9m+12))=0



Domain of the equation: 2(14m+4)!=0

m∈R





Domain of the equation: 3(9m+12))!=0

m∈R



We calculate fractions


(3m9/(2(14m+4)*3(9m+12)))+(-2m1/(2(14m+4)*3(9m+12)))=0



We calculate terms in parentheses: +(3m9/(2(14m+4)*3(9m+12))), so:

3m9/(2(14m+4)*3(9m+12))

We multiply all the terms by the denominator


3m9

We add all the numbers together, and all the variables

3m^9

We do not support empression: m^9

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