1/2(16-10x)-2-3x=2(3-x)

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Solution for 1/2(16-10x)-2-3x=2(3-x) equation: 



1/2(16-10x)-2-3x=2(3-x)

We move all terms to the left:

1/2(16-10x)-2-3x-(2(3-x))=0



Domain of the equation: 2(16-10x)!=0

x∈R



We add all the numbers together, and all the variables

1/2(-10x+16)-3x-(2(-1x+3))-2=0

We add all the numbers together, and all the variables

-3x+1/2(-10x+16)-(2(-1x+3))-2=0

We multiply all the terms by the denominator


-3x*2(-10x+16)-((2(-1x+3)))*2(-10x+16)-2*2(-10x+16)+1=0



We calculate terms in parentheses: -((2(-1x+3)))*2(-10x+16), so:

(2(-1x+3)))*2(-10x+16

We add all the numbers together, and all the variables

-10x+(2(-1x+3)))*2(+16

Back to the equation:

-(-10x+(2(-1x+3)))*2(+16)



We add all the numbers together, and all the variables

-3x*2(-10x+16)-(-10x+(2(-1x+3)))*216-2*2(-10x+16)+1=0

Wy multiply elements

-6x^2(--(-10x+(2(-1x+3)))*216-4x(-+1=0

We use the square of the difference formula

-6x^2(+(-10x+(2(-1x+3)))*216-4x(-1=0

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