1/2(16-8x)-8=4x+4(x-2)

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Solution for 1/2(16-8x)-8=4x+4(x-2) equation: 



1/2(16-8x)-8=4x+4(x-2)

We move all terms to the left:

1/2(16-8x)-8-(4x+4(x-2))=0



Domain of the equation: 2(16-8x)!=0

x∈R



We add all the numbers together, and all the variables

1/2(-8x+16)-(4x+4(x-2))-8=0

We multiply all the terms by the denominator


-((4x+4(x-2)))*2(-8x+16)-8*2(-8x+16)+1=0



We calculate terms in parentheses: -((4x+4(x-2)))*2(-8x+16), so:

(4x+4(x-2)))*2(-8x+16

We add all the numbers together, and all the variables

-8x+(4x+4(x-2)))*2(+16

Back to the equation:

-(-8x+(4x+4(x-2)))*2(+16)



We add all the numbers together, and all the variables

-(-8x+(4x+4(x-2)))*216-8*2(-8x+16)+1=0

Wy multiply elements

-(-8x+(4x+4(x-2)))*216-16x(-+1=0

We use the square of the difference formula

-(-8x+(4x+4(x-2)))*216-16x(-1=0

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