1/2(16-i)=3/2i

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Solution for 1/2(16-i)=3/2i equation: 



1/2(16-i)=3/2i

We move all terms to the left:

1/2(16-i)-(3/2i)=0



Domain of the equation: 2(16-i)!=0

i∈R





Domain of the equation: 2i)!=0

i!=0/1

i!=0

i∈R



We add all the numbers together, and all the variables

1/2(-1i+16)-(+3/2i)=0

We get rid of parentheses

1/2(-1i+16)-3/2i=0

We calculate fractions


2i/(-4i^2+64i)+(-6i(-)/(-4i^2+64i)=0



We calculate terms in parentheses: +(-6i(-)/(-4i^2+64i), so:

-6i(-)/(-4i^2+64i

We add all the numbers together, and all the variables

-6i0/(-4i^2+64i

We multiply all the terms by the denominator


-6i0

We add all the numbers together, and all the variables

-6i

Back to the equation:

+(-6i)



We get rid of parentheses

2i/(-4i^2+64i)-6i=0

We multiply all the terms by the denominator


-6i*(-4i^2+64i)+2i=0

We multiply parentheses

24i^3-384i^2+2i=0

We do not support eipression: i^3

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