1/2(16e+48)=-1/3(24e-24)

Solution for 1/2(16e+48)=-1/3(24e-24) equation:

1/2(16e+48)=-1/3(24e-24)

We move all terms to the left:

1/2(16e+48)-(-1/3(24e-24))=0


Domain of the equation: 2(16e+48)!=0

e∈R



Domain of the equation: 3(24e-24))!=0

e∈R


We calculate fractions


(3e2/(2(16e+48)*3(24e-24)))+(-(-2e1)/(2(16e+48)*3(24e-24)))=0


We calculate terms in parentheses: +(3e2/(2(16e+48)*3(24e-24))), so:

3e2/(2(16e+48)*3(24e-24))

We multiply all the terms by the denominator


3e2

We add all the numbers together, and all the variables

3e^2

Back to the equation:

+(3e^2)



We calculate terms in parentheses: +(-(-2e1)/(2(16e+48)*3(24e-24))), so:

-(-2e1)/(2(16e+48)*3(24e-24))

We add all the numbers together, and all the variables

-(-2e)/(2(16e+48)*3(24e-24))

We multiply all the terms by the denominator


-(-2e)

We get rid of parentheses

2e

Back to the equation:

+(2e)


a = 3; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·3·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*3}=\frac{-4}{6}
=-2/3
$
$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*3}=\frac{0}{6}
=0
$