1/2(16x+24)+3(2/3x-9)=-(x+3)-12

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Solution for 1/2(16x+24)+3(2/3x-9)=-(x+3)-12 equation: 



1/2(16x+24)+3(2/3x-9)=-(x+3)-12

We move all terms to the left:

1/2(16x+24)+3(2/3x-9)-(-(x+3)-12)=0



Domain of the equation: 2(16x+24)!=0

x∈R





Domain of the equation: 3x-9)!=0

x∈R



We multiply parentheses

1/2(16x+24)+6x-(-(x+3)-12)-27=0

We multiply all the terms by the denominator


6x*2(16x+24)-((-(x+3)-12))*2(16x+24)-27*2(16x+24)+1=0



We calculate terms in parentheses: -((-(x+3)-12))*2(16x+24), so:

(-(x+3)-12))*2(16x+24



Wy multiply elements

12x^2(1-((-(x+3)-12))*2(16x+24)-54x(1+1=0

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