1/2(16x+4)-19=-1/3(9x-12)

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Solution for 1/2(16x+4)-19=-1/3(9x-12) equation: 



1/2(16x+4)-19=-1/3(9x-12)

We move all terms to the left:

1/2(16x+4)-19-(-1/3(9x-12))=0



Domain of the equation: 2(16x+4)!=0

x∈R





Domain of the equation: 3(9x-12))!=0

x∈R



We calculate fractions


(3x9/(2(16x+4)*3(9x-12)))+(-(-2x1)/(2(16x+4)*3(9x-12)))-19=0



We calculate terms in parentheses: +(3x9/(2(16x+4)*3(9x-12))), so:

3x9/(2(16x+4)*3(9x-12))

We multiply all the terms by the denominator


3x9

We add all the numbers together, and all the variables

3x^9

We do not support expression: x^9

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