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1/2(16x+5)-3=19-5x
We move all terms to the left:
1/2(16x+5)-3-(19-5x)=0
Domain of the equation: 2(16x+5)!=0We add all the numbers together, and all the variables
x∈R
1/2(16x+5)-(-5x+19)-3=0
We get rid of parentheses
1/2(16x+5)+5x-19-3=0
We multiply all the terms by the denominator
5x*2(16x+5)-19*2(16x+5)-3*2(16x+5)+1=0
Wy multiply elements
10x^2(1-38x(1-6x(1+1=0
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