1/2(16x-10)=67

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Solution for 1/2(16x-10)=67 equation:



1/2(16x-10)=67
We move all terms to the left:
1/2(16x-10)-(67)=0
Domain of the equation: 2(16x-10)!=0
x∈R
We multiply all the terms by the denominator
-67*2(16x-10)+1=0
Wy multiply elements
-134x(1+1=0

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