1/2(16y-32)=3y-12+5y-4

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Solution for 1/2(16y-32)=3y-12+5y-4 equation: 



1/2(16y-32)=3y-12+5y-4

We move all terms to the left:

1/2(16y-32)-(3y-12+5y-4)=0



Domain of the equation: 2(16y-32)!=0

y∈R



We add all the numbers together, and all the variables

1/2(16y-32)-(8y-16)=0

We get rid of parentheses

1/2(16y-32)-8y+16=0

We multiply all the terms by the denominator


-8y*2(16y-32)+16*2(16y-32)+1=0

Wy multiply elements

-16y^2(1+32y(1+1=0

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