1/2(18-12x)=1/3(6-15x)

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Solution for 1/2(18-12x)=1/3(6-15x) equation:



1/2(18-12x)=1/3(6-15x)
We move all terms to the left:
1/2(18-12x)-(1/3(6-15x))=0
Domain of the equation: 2(18-12x)!=0
x∈R
Domain of the equation: 3(6-15x))!=0
x∈R
We add all the numbers together, and all the variables
1/2(-12x+18)-(1/3(-15x+6))=0
We calculate fractions
(3x(-)/(2(-12x+18)*3(-15x+6)))+(-2x0/(2(-12x+18)*3(-15x+6)))=0
We calculate terms in parentheses: +(3x(-)/(2(-12x+18)*3(-15x+6))), so:
3x(-)/(2(-12x+18)*3(-15x+6))
We add all the numbers together, and all the variables
3x0/(2(-12x+18)*3(-15x+6))
We multiply all the terms by the denominator
3x0
We add all the numbers together, and all the variables
3x
Back to the equation:
+(3x)
We calculate terms in parentheses: +(-2x0/(2(-12x+18)*3(-15x+6))), so:
-2x0/(2(-12x+18)*3(-15x+6))
We multiply all the terms by the denominator
-2x0
We add all the numbers together, and all the variables
-2x
Back to the equation:
+(-2x)
We get rid of parentheses
3x-2x=0
We add all the numbers together, and all the variables
x=0

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