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1/2(18-12x)=6-3x
We move all terms to the left:
1/2(18-12x)-(6-3x)=0
Domain of the equation: 2(18-12x)!=0We add all the numbers together, and all the variables
x∈R
1/2(-12x+18)-(-3x+6)=0
We get rid of parentheses
1/2(-12x+18)+3x-6=0
We multiply all the terms by the denominator
3x*2(-12x+18)-6*2(-12x+18)+1=0
Wy multiply elements
6x^2(--12x(-+1=0
We use the square of the difference formula
6x^2(+12x(-1=0
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