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1/2(18x+9)=3/2(x-2)
We move all terms to the left:
1/2(18x+9)-(3/2(x-2))=0
Domain of the equation: 2(18x+9)!=0
x∈R
Domain of the equation: 2(x-2))!=0We calculate fractions
x∈R
(2xx/(2(18x+9)*2(x-2)))+(-6x1/(2(18x+9)*2(x-2)))=0
We calculate terms in parentheses: +(2xx/(2(18x+9)*2(x-2))), so:
2xx/(2(18x+9)*2(x-2))
We multiply all the terms by the denominator
2xx
Back to the equation:
+(2xx)
We calculate terms in parentheses: +(-6x1/(2(18x+9)*2(x-2))), so:We get rid of parentheses
-6x1/(2(18x+9)*2(x-2))
We multiply all the terms by the denominator
-6x1
We add all the numbers together, and all the variables
-6x
Back to the equation:
+(-6x)
2xx-6x=0
We add all the numbers together, and all the variables
-6x+2xx=0
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