1/2(1x-12)=1/4(1x+16)

Solution for 1/2(1x-12)=1/4(1x+16) equation:

1/2(1x-12)=1/4(1x+16)

We move all terms to the left:

1/2(1x-12)-(1/4(1x+16))=0


Domain of the equation: 2(1x-12)!=0

x∈R



Domain of the equation: 4(1x+16))!=0

x∈R


We add all the numbers together, and all the variables

1/2(x-12)-(1/4(x+16))=0

We calculate fractions


(4xx/(2(x-12)*4(x+16)))+(-2xx/(2(x-12)*4(x+16)))=0


We calculate terms in parentheses: +(4xx/(2(x-12)*4(x+16))), so:

4xx/(2(x-12)*4(x+16))

We multiply all the terms by the denominator


4xx

Back to the equation:

+(4xx)



We calculate terms in parentheses: +(-2xx/(2(x-12)*4(x+16))), so:

-2xx/(2(x-12)*4(x+16))

We multiply all the terms by the denominator


-2xx

Back to the equation:

+(-2xx)


We get rid of parentheses

4xx-2xx=0