1/2(2+2/3x)=6/5+(1/3x-1/5)

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Solution for 1/2(2+2/3x)=6/5+(1/3x-1/5) equation: 


x in (-oo:+oo)

(1/2)*((2/3)*x+2) = (1/3)*x+6/5-(1/5) // - (1/3)*x+6/5-(1/5)

(1/2)*((2/3)*x+2)-((1/3)*x)-(6/5)+1/5 = 0

(1/2)*((2/3)*x+2)+(-1/3)*x-6/5+1/5 = 0

1/2*(2/3*x+2)-x/3-6/5+1/5 = 0

(1/2*3*5*(2/3*x+2))/(3*5)+(5*(-x))/(3*5)+(-6*3)/(3*5)+(1*3)/(3*5) = 0

1/2*3*5*(2/3*x+2)+5*(-x)-6*3+1*3 = 0

3-18+15 = 0

3-3 = 0

0 = 0

0/(3*5) = 0

0/(3*5) = 0 // * 3*5

0 = 0

x belongs to the empty set

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