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1/2(2-2x)=13+x
We move all terms to the left:
1/2(2-2x)-(13+x)=0
Domain of the equation: 2(2-2x)!=0We add all the numbers together, and all the variables
x∈R
1/2(-2x+2)-(x+13)=0
We get rid of parentheses
1/2(-2x+2)-x-13=0
We multiply all the terms by the denominator
-x*2(-2x+2)-13*2(-2x+2)+1=0
Wy multiply elements
-2x^2(--26x(-+1=0
We use the square of the difference formula
-2x^2(+26x(-1=0
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