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1/2(2-4)+3x=-2(x-5)
We move all terms to the left:
1/2(2-4)+3x-(-2(x-5))=0
We add all the numbers together, and all the variables
3x-(-2(x-5))+1/2(-2)=0
We multiply all the terms by the denominator
3x*2(-2)-((-2(x-5)))*2(-2)+1=0
We calculate terms in parentheses: -((-2(x-5)))*2(-2), so:Wy multiply elements
(-2(x-5)))*2(-2
6x^2(--((-2(x-5)))*2(-2)+1=0
We use the square of the difference formula
6x^2(+((-2(x-5)))*2(-2)+1=0
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