1/2(2-4x)+8x=-3(4-2x)

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Solution for 1/2(2-4x)+8x=-3(4-2x) equation: 



1/2(2-4x)+8x=-3(4-2x)

We move all terms to the left:

1/2(2-4x)+8x-(-3(4-2x))=0



Domain of the equation: 2(2-4x)!=0

x∈R



We add all the numbers together, and all the variables

1/2(-4x+2)+8x-(-3(-2x+4))=0

We add all the numbers together, and all the variables

8x+1/2(-4x+2)-(-3(-2x+4))=0

We multiply all the terms by the denominator


8x*2(-4x+2)-((-3(-2x+4)))*2(-4x+2)+1=0



We calculate terms in parentheses: -((-3(-2x+4)))*2(-4x+2), so:

(-3(-2x+4)))*2(-4x+2

We add all the numbers together, and all the variables

-4x+(-3(-2x+4)))*2(+2

Back to the equation:

-(-4x+(-3(-2x+4)))*2(+2)



We add all the numbers together, and all the variables

8x*2(-4x+2)-(-4x+(-3(-2x+4)))*22+1=0

Wy multiply elements

16x^2(--(-4x+(-3(-2x+4)))*22+1=0

We use the square of the difference formula

16x^2(+(-4x+(-3(-2x+4)))*22+1=0

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