1/2(26-14y)+2y=-4(8+y)-10+4y

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Solution for 1/2(26-14y)+2y=-4(8+y)-10+4y equation:



1/2(26-14y)+2y=-4(8+y)-10+4y
We move all terms to the left:
1/2(26-14y)+2y-(-4(8+y)-10+4y)=0
Domain of the equation: 2(26-14y)!=0
y∈R
We add all the numbers together, and all the variables
1/2(-14y+26)+2y-(-4(y+8)-10+4y)=0
We add all the numbers together, and all the variables
2y+1/2(-14y+26)-(-4(y+8)-10+4y)=0
We multiply all the terms by the denominator
2y*2(-14y+26)-((-4(y+8)-10+4y))*2(-14y+26)+1=0
We calculate terms in parentheses: -((-4(y+8)-10+4y))*2(-14y+26), so:
(-4(y+8)-10+4y))*2(-14y+26
We add all the numbers together, and all the variables
-14y+(-4(y+8)-10+4y))*2(+26
Back to the equation:
-(-14y+(-4(y+8)-10+4y))*2(+26)
We add all the numbers together, and all the variables
2y*2(-14y+26)-(-14y+(-4(y+8)-10+4y))*226+1=0
Wy multiply elements
4y^2(--(-14y+(-4(y+8)-10+4y))*226+1=0
We use the square of the difference formula
4y^2(+(-14y+(-4(y+8)-10+4y))*226+1=0

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