1/2(26-14y)+2y=-4(8+y)-10+4y

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Solution for 1/2(26-14y)+2y=-4(8+y)-10+4y equation: 



1/2(26-14y)+2y=-4(8+y)-10+4y

We move all terms to the left:

1/2(26-14y)+2y-(-4(8+y)-10+4y)=0



Domain of the equation: 2(26-14y)!=0

y∈R



We add all the numbers together, and all the variables

1/2(-14y+26)+2y-(-4(y+8)-10+4y)=0

We add all the numbers together, and all the variables

2y+1/2(-14y+26)-(-4(y+8)-10+4y)=0

We multiply all the terms by the denominator


2y*2(-14y+26)-((-4(y+8)-10+4y))*2(-14y+26)+1=0



We calculate terms in parentheses: -((-4(y+8)-10+4y))*2(-14y+26), so:

(-4(y+8)-10+4y))*2(-14y+26

We add all the numbers together, and all the variables

-14y+(-4(y+8)-10+4y))*2(+26

Back to the equation:

-(-14y+(-4(y+8)-10+4y))*2(+26)



We add all the numbers together, and all the variables

2y*2(-14y+26)-(-14y+(-4(y+8)-10+4y))*226+1=0

Wy multiply elements

4y^2(--(-14y+(-4(y+8)-10+4y))*226+1=0

We use the square of the difference formula

4y^2(+(-14y+(-4(y+8)-10+4y))*226+1=0

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