1/2(27-x)=9/2+1/10(7x-54)

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Solution for 1/2(27-x)=9/2+1/10(7x-54) equation: 


x in (-oo:+oo)

(1/2)*(27-x) = (1/10)*(7*x-54)+9/2 // - (1/10)*(7*x-54)+9/2

(1/2)*(27-x)-((1/10)*(7*x-54))-(9/2) = 0

(1/2)*(27-x)+(-1/10)*(7*x-54)-9/2 = 0

1/2*(27-x)-1/10*(7*x-54)-9/2 = 0

(1/2*2*(27-x))/2+(-1/10*2*(7*x-54))/2-9/2 = 0

1/2*2*(27-x)-1/10*2*(7*x-54)-9 = 0

189/5-12/5*x-9 = 0

144/5-12/5*x = 0

(144/5-12/5*x)/2 = 0

(144/5-12/5*x)/2 = 0 // * 2

144/5-12/5*x = 0

144/5-12/5*x = 0 // - 144/5

-12/5*x = -144/5 // : -12/5

x = -144/5/(-12/5)

x = 12

x = 12

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