1/2(28+2x)=5(x-2)

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Solution for 1/2(28+2x)=5(x-2) equation: 



1/2(28+2x)=5(x-2)

We move all terms to the left:

1/2(28+2x)-(5(x-2))=0



Domain of the equation: 2(28+2x)!=0

x∈R



We add all the numbers together, and all the variables

1/2(2x+28)-(5(x-2))=0

We multiply all the terms by the denominator


-((5(x-2)))*2(2x+28)+1=0



We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*2(2x+28), so:

(5(x-2)))*2(2x+28





We calculate terms in parentheses: -((5(x-2)))*

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