1/2(2a+3)-4a-8)=7

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Solution for 1/2(2a+3)-4a-8)=7 equation: 



1/2(2a+3)-4a-8)=7

We move all terms to the left:

1/2(2a+3)-4a-8)-(7)=0



Domain of the equation: 2(2a+3)!=0

a∈R



We add all the numbers together, and all the variables

-4a+1/2(2a+3)=0

We multiply all the terms by the denominator


-4a*2(2a+3)+1=0

Wy multiply elements

-8a^2(2+1=0

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