1/2(2h-1)=1/4(2h+12)

Solution for 1/2(2h-1)=1/4(2h+12) equation:

1/2(2h-1)=1/4(2h+12)

We move all terms to the left:

1/2(2h-1)-(1/4(2h+12))=0


Domain of the equation: 2(2h-1)!=0

h∈R



Domain of the equation: 4(2h+12))!=0

h∈R


We calculate fractions


(4h2/(2(2h-1)*4(2h+12)))+(-2h2/(2(2h-1)*4(2h+12)))=0


We calculate terms in parentheses: +(4h2/(2(2h-1)*4(2h+12))), so:

4h2/(2(2h-1)*4(2h+12))

We multiply all the terms by the denominator


4h2

We add all the numbers together, and all the variables

4h^2

Back to the equation:

+(4h^2)



We calculate terms in parentheses: +(-2h2/(2(2h-1)*4(2h+12))), so:

-2h2/(2(2h-1)*4(2h+12))

We multiply all the terms by the denominator


-2h2

We add all the numbers together, and all the variables

-2h^2

Back to the equation:

+(-2h^2)


We add all the numbers together, and all the variables

4h^2+(-2h^2)=0

We get rid of parentheses

4h^2-2h^2=0

We add all the numbers together, and all the variables

2h^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$h=\frac{-b}{2a}=\frac{0}{4}=0$