1/2(2m-20)=1/4(8+8m)

Solution for 1/2(2m-20)=1/4(8+8m) equation:

1/2(2m-20)=1/4(8+8m)

We move all terms to the left:

1/2(2m-20)-(1/4(8+8m))=0


Domain of the equation: 2(2m-20)!=0

m∈R



Domain of the equation: 4(8+8m))!=0

m∈R


We add all the numbers together, and all the variables

1/2(2m-20)-(1/4(8m+8))=0

We calculate fractions


(4m8/(2(2m-20)*4(8m+8)))+(-2m2/(2(2m-20)*4(8m+8)))=0


We calculate terms in parentheses: +(4m8/(2(2m-20)*4(8m+8))), so:

4m8/(2(2m-20)*4(8m+8))

We multiply all the terms by the denominator


4m8

We add all the numbers together, and all the variables

4m^8

We do not support empression: m^8