1/2(2n-20)+4n=-3(5n-10)

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Solution for 1/2(2n-20)+4n=-3(5n-10) equation: 



1/2(2n-20)+4n=-3(5n-10)

We move all terms to the left:

1/2(2n-20)+4n-(-3(5n-10))=0



Domain of the equation: 2(2n-20)!=0

n∈R



We add all the numbers together, and all the variables

4n+1/2(2n-20)-(-3(5n-10))=0

We multiply all the terms by the denominator


4n*2(2n-20)-((-3(5n-10)))*2(2n-20)+1=0



We calculate terms in parentheses: -((-3(5n-10)))*2(2n-20), so:

(-3(5n-10)))*2(2n-20



Wy multiply elements

8n^2(2-((-3(5n-10)))*2(2n-20)+1=0

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