1/2(2x+1)=1/2(3+2x)

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Solution for 1/2(2x+1)=1/2(3+2x) equation: 



1/2(2x+1)=1/2(3+2x)

We move all terms to the left:

1/2(2x+1)-(1/2(3+2x))=0



Domain of the equation: 2(2x+1)!=0

x∈R





Domain of the equation: 2(3+2x))!=0

x∈R



We add all the numbers together, and all the variables

1/2(2x+1)-(1/2(2x+3))=0

We calculate fractions


(2x2/(2(2x+1)*2(2x+3)))+(-2x2/(2(2x+1)*2(2x+3)))=0



We calculate terms in parentheses: +(2x2/(2(2x+1)*2(2x+3))), so:

2x2/(2(2x+1)*2(2x+3))

We multiply all the terms by the denominator


2x2

We add all the numbers together, and all the variables

2x^2

Back to the equation:

+(2x^2)





We calculate terms in parentheses: +(-2x2/(2(2x+1)*2(2x+3))), so:

-2x2/(2(2x+1)*2(2x+3))

We multiply all the terms by the denominator


-2x2

We add all the numbers together, and all the variables

-2x^2

Back to the equation:

+(-2x^2)



We add all the numbers together, and all the variables

2x^2+(-2x^2)=0

We get rid of parentheses

2x^2-2x^2=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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