1/2(2x+2)=2/3(x-1)

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Solution for 1/2(2x+2)=2/3(x-1) equation: 



1/2(2x+2)=2/3(x-1)

We move all terms to the left:

1/2(2x+2)-(2/3(x-1))=0



Domain of the equation: 2(2x+2)!=0

x∈R





Domain of the equation: 3(x-1))!=0

x∈R



We calculate fractions


(3xx/(2(2x+2)*3(x-1)))+(-4x2/(2(2x+2)*3(x-1)))=0



We calculate terms in parentheses: +(3xx/(2(2x+2)*3(x-1))), so:

3xx/(2(2x+2)*3(x-1))

We multiply all the terms by the denominator


3xx

Back to the equation:

+(3xx)





We calculate terms in parentheses: +(-4x2/(2(2x+2)*3(x-1))), so:

-4x2/(2(2x+2)*3(x-1))

We multiply all the terms by the denominator


-4x2

We add all the numbers together, and all the variables

-4x^2

Back to the equation:

+(-4x^2)



We get rid of parentheses

-4x^2+3xx=0

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