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1/2(2x+3)+4x=9x+10
We move all terms to the left:
1/2(2x+3)+4x-(9x+10)=0
Domain of the equation: 2(2x+3)!=0We add all the numbers together, and all the variables
x∈R
4x+1/2(2x+3)-(9x+10)=0
We get rid of parentheses
4x+1/2(2x+3)-9x-10=0
We multiply all the terms by the denominator
4x*2(2x+3)-9x*2(2x+3)-10*2(2x+3)+1=0
Wy multiply elements
8x^2(2-18x^2(2-20x(2+1=0
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