1/2(2x+4)=2/3(3x+6)

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Solution for 1/2(2x+4)=2/3(3x+6) equation:



1/2(2x+4)=2/3(3x+6)
We move all terms to the left:
1/2(2x+4)-(2/3(3x+6))=0
Domain of the equation: 2(2x+4)!=0
x∈R
Domain of the equation: 3(3x+6))!=0
x∈R
We calculate fractions
(3x3/(2(2x+4)*3(3x+6)))+(-4x2/(2(2x+4)*3(3x+6)))=0
We calculate terms in parentheses: +(3x3/(2(2x+4)*3(3x+6))), so:
3x3/(2(2x+4)*3(3x+6))
We multiply all the terms by the denominator
3x3
We add all the numbers together, and all the variables
3x^3
We do not support expression: x^3

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