1/2(2x+4)=2/3(3x+6)

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Solution for 1/2(2x+4)=2/3(3x+6) equation: 



1/2(2x+4)=2/3(3x+6)

We move all terms to the left:

1/2(2x+4)-(2/3(3x+6))=0



Domain of the equation: 2(2x+4)!=0

x∈R





Domain of the equation: 3(3x+6))!=0

x∈R



We calculate fractions


(3x3/(2(2x+4)*3(3x+6)))+(-4x2/(2(2x+4)*3(3x+6)))=0



We calculate terms in parentheses: +(3x3/(2(2x+4)*3(3x+6))), so:

3x3/(2(2x+4)*3(3x+6))

We multiply all the terms by the denominator


3x3

We add all the numbers together, and all the variables

3x^3

We do not support expression: x^3

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