1/2(2x+5)=-1/6(x-4)

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Solution for 1/2(2x+5)=-1/6(x-4) equation: 



1/2(2x+5)=-1/6(x-4)

We move all terms to the left:

1/2(2x+5)-(-1/6(x-4))=0



Domain of the equation: 2(2x+5)!=0

x∈R





Domain of the equation: 6(x-4))!=0

x∈R



We calculate fractions


(6xx/(2(2x+5)*6(x-4)))+(-(-2x2)/(2(2x+5)*6(x-4)))=0



We calculate terms in parentheses: +(6xx/(2(2x+5)*6(x-4))), so:

6xx/(2(2x+5)*6(x-4))

We multiply all the terms by the denominator


6xx

Back to the equation:

+(6xx)





We calculate terms in parentheses: +(-(-2x2)/(2(2x+5)*6(x-4))), so:

-(-2x2)/(2(2x+5)*6(x-4))

We add all the numbers together, and all the variables

-(-2x^2)/(2(2x+5)*6(x-4))

We multiply all the terms by the denominator


-(-2x^2)

We get rid of parentheses

2x^2

Back to the equation:

+(2x^2)



determiningTheFunctionDomain
2x^2+6xx=0

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