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1/2(2x+5)=1/4(x-4)
We move all terms to the left:
1/2(2x+5)-(1/4(x-4))=0
Domain of the equation: 2(2x+5)!=0
x∈R
Domain of the equation: 4(x-4))!=0We calculate fractions
x∈R
(4xx/(2(2x+5)*4(x-4)))+(-2x2/(2(2x+5)*4(x-4)))=0
We calculate terms in parentheses: +(4xx/(2(2x+5)*4(x-4))), so:
4xx/(2(2x+5)*4(x-4))
We multiply all the terms by the denominator
4xx
Back to the equation:
+(4xx)
We calculate terms in parentheses: +(-2x2/(2(2x+5)*4(x-4))), so:We get rid of parentheses
-2x2/(2(2x+5)*4(x-4))
We multiply all the terms by the denominator
-2x2
We add all the numbers together, and all the variables
-2x^2
Back to the equation:
+(-2x^2)
-2x^2+4xx=0
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