1/2(2x+8)=1/3(x+2)

Solution for 1/2(2x+8)=1/3(x+2) equation:

1/2(2x+8)=1/3(x+2)

We move all terms to the left:

1/2(2x+8)-(1/3(x+2))=0


Domain of the equation: 2(2x+8)!=0

x∈R



Domain of the equation: 3(x+2))!=0

x∈R


We calculate fractions


(3xx/(2(2x+8)*3(x+2)))+(-2x2/(2(2x+8)*3(x+2)))=0


We calculate terms in parentheses: +(3xx/(2(2x+8)*3(x+2))), so:

3xx/(2(2x+8)*3(x+2))

We multiply all the terms by the denominator


3xx

Back to the equation:

+(3xx)



We calculate terms in parentheses: +(-2x2/(2(2x+8)*3(x+2))), so:

-2x2/(2(2x+8)*3(x+2))

We multiply all the terms by the denominator


-2x2

We add all the numbers together, and all the variables

-2x^2

Back to the equation:

+(-2x^2)


We get rid of parentheses

-2x^2+3xx=0