1/2(2x-10)+2x=28

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Solution for 1/2(2x-10)+2x=28 equation: 



1/2(2x-10)+2x=28

We move all terms to the left:

1/2(2x-10)+2x-(28)=0



Domain of the equation: 2(2x-10)!=0

x∈R



We add all the numbers together, and all the variables

2x+1/2(2x-10)-28=0

We multiply all the terms by the denominator


2x*2(2x-10)-28*2(2x-10)+1=0

Wy multiply elements

4x^2(2-56x(2+1=0

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