1/2(2x-10)+2x=28

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Solution for 1/2(2x-10)+2x=28 equation:



1/2(2x-10)+2x=28
We move all terms to the left:
1/2(2x-10)+2x-(28)=0
Domain of the equation: 2(2x-10)!=0
x∈R
We add all the numbers together, and all the variables
2x+1/2(2x-10)-28=0
We multiply all the terms by the denominator
2x*2(2x-10)-28*2(2x-10)+1=0
Wy multiply elements
4x^2(2-56x(2+1=0

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