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1/2(2x-12+6x-8)=3x-1
We move all terms to the left:
1/2(2x-12+6x-8)-(3x-1)=0
Domain of the equation: 2(2x-12+6x-8)!=0We add all the numbers together, and all the variables
x∈R
1/2(8x-20)-(3x-1)=0
We get rid of parentheses
1/2(8x-20)-3x+1=0
We multiply all the terms by the denominator
-3x*2(8x-20)+1*2(8x-20)+1=0
Wy multiply elements
-6x^2(8+2x(8+1=0
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