1/2(2x-4)+10=4x+41

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Solution for 1/2(2x-4)+10=4x+41 equation: 



1/2(2x-4)+10=4x+41

We move all terms to the left:

1/2(2x-4)+10-(4x+41)=0



Domain of the equation: 2(2x-4)!=0

x∈R



We get rid of parentheses

1/2(2x-4)-4x-41+10=0

We multiply all the terms by the denominator


-4x*2(2x-4)-41*2(2x-4)+10*2(2x-4)+1=0

Wy multiply elements

-8x^2(2-82x(2+20x(2+1=0

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