1/2(2x-4)+x=8

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Solution for 1/2(2x-4)+x=8 equation: 



1/2(2x-4)+x=8

We move all terms to the left:

1/2(2x-4)+x-(8)=0



Domain of the equation: 2(2x-4)!=0

x∈R



We add all the numbers together, and all the variables

x+1/2(2x-4)-8=0

We multiply all the terms by the denominator


x*2(2x-4)-8*2(2x-4)+1=0

Wy multiply elements

2x^2(2-16x(2+1=0

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