1/2(2x-4)=1/2(x-8)

Solution for 1/2(2x-4)=1/2(x-8) equation:

1/2(2x-4)=1/2(x-8)

We move all terms to the left:

1/2(2x-4)-(1/2(x-8))=0


Domain of the equation: 2(2x-4)!=0

x∈R



Domain of the equation: 2(x-8))!=0

x∈R


We calculate fractions


(2xx/(2(2x-4)*2(x-8)))+(-2x2/(2(2x-4)*2(x-8)))=0


We calculate terms in parentheses: +(2xx/(2(2x-4)*2(x-8))), so:

2xx/(2(2x-4)*2(x-8))

We multiply all the terms by the denominator


2xx

Back to the equation:

+(2xx)



We calculate terms in parentheses: +(-2x2/(2(2x-4)*2(x-8))), so:

-2x2/(2(2x-4)*2(x-8))

We multiply all the terms by the denominator


-2x2

We add all the numbers together, and all the variables

-2x^2

Back to the equation:

+(-2x^2)


We get rid of parentheses

-2x^2+2xx=0