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1/2(2x-5)+x=x+7
We move all terms to the left:
1/2(2x-5)+x-(x+7)=0
Domain of the equation: 2(2x-5)!=0We add all the numbers together, and all the variables
x∈R
x+1/2(2x-5)-(x+7)=0
We get rid of parentheses
x+1/2(2x-5)-x-7=0
We multiply all the terms by the denominator
x*2(2x-5)-x*2(2x-5)-7*2(2x-5)+1=0
Wy multiply elements
2x^2(2-2x^2(2-14x(2+1=0
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