1/2(2x-8)+x-2=2(x-3)

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Solution for 1/2(2x-8)+x-2=2(x-3) equation: 



1/2(2x-8)+x-2=2(x-3)

We move all terms to the left:

1/2(2x-8)+x-2-(2(x-3))=0



Domain of the equation: 2(2x-8)!=0

x∈R



We add all the numbers together, and all the variables

x+1/2(2x-8)-(2(x-3))-2=0

We multiply all the terms by the denominator


x*2(2x-8)-((2(x-3)))*2(2x-8)-2*2(2x-8)+1=0



We calculate terms in parentheses: -((2(x-3)))*2(2x-8), so:

(2(x-3)))*2(2x-8



Wy multiply elements

2x^2(2-((2(x-3)))*2(2x-8)-4x(2+1=0

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