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1/2(2x-8)=1/3x
We move all terms to the left:
1/2(2x-8)-(1/3x)=0
Domain of the equation: 2(2x-8)!=0
x∈R
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/2(2x-8)-(+1/3x)=0
We get rid of parentheses
1/2(2x-8)-1/3x=0
We calculate fractions
3x/(12x^2-48x)+(-2x2/(12x^2-48x)=0
We calculate terms in parentheses: +(-2x2/(12x^2-48x), so:We get rid of parentheses
-2x2/(12x^2-48x
We multiply all the terms by the denominator
-2x2
We add all the numbers together, and all the variables
-2x^2
Back to the equation:
+(-2x^2)
-2x^2+3x/(12x^2-48x)=0
We multiply all the terms by the denominator
-2x^2*(12x^2-48x)+3x=0
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