1/2(2x-8)=2/3(x+7)

Solution for 1/2(2x-8)=2/3(x+7) equation:

1/2(2x-8)=2/3(x+7)

We move all terms to the left:

1/2(2x-8)-(2/3(x+7))=0


Domain of the equation: 2(2x-8)!=0

x∈R



Domain of the equation: 3(x+7))!=0

x∈R


We calculate fractions


(3xx/(2(2x-8)*3(x+7)))+(-4x2/(2(2x-8)*3(x+7)))=0


We calculate terms in parentheses: +(3xx/(2(2x-8)*3(x+7))), so:

3xx/(2(2x-8)*3(x+7))

We multiply all the terms by the denominator


3xx

Back to the equation:

+(3xx)



We calculate terms in parentheses: +(-4x2/(2(2x-8)*3(x+7))), so:

-4x2/(2(2x-8)*3(x+7))

We multiply all the terms by the denominator


-4x2

We add all the numbers together, and all the variables

-4x^2

Back to the equation:

+(-4x^2)


We get rid of parentheses

-4x^2+3xx=0